No idea?

How about:

A man lives in a tower block on the 10th floor. In the morning he gets in the lift and travels all the way down to go to work. When he returns in the evening he gets into the lift and if he is alone he gets off at the fifth floor and walks up the stairs to the tenth floor. However if there is someone in the lift with him he travels to the tenth floor. Why?

Also:

A car is driving along the motorway at a constant speed when one of the wheels falls off. Assuming there is no rolling resistance from the road why does the wheel over take the car?

kbannon wrote: Im just dead brainy like!

Killian!?

I thought it was a picture of the lead singer from the Pogues..

Derek M5 wrote: Anthony and Cleopatra were goldfish whose bowl was knocked over by a clumsy dog - we've got one like that at home so it was easy!!   And while you're at it............   A man is pushing his car. He stops when he reaches a hotel at which point he knows he is bankrupt. Why?

It's his hotel and it's closed due to insolvency?

Peter Fenwick wrote: No idea? How about: A man lives in a tower block on the 10th floor. In the morning he gets in the lift and travels all the way down to go to work. When he returns in the evening he gets into the lift and if he is alone he gets off at the fifth floor and walks up the stairs to the tenth floor. However if there is someone in the lift with him he travels to the tenth floor. Why? Also: A car is driving along the motorway at a constant speed when one of the wheels falls off. Assuming there is no rolling resistance from the road why does the wheel over take the car?

First one, the man is a midget and can't reach the 10th floor button.

2nd, it was a reliant robin drive wheel?

Correct on the first one. The second is a bit more techy. It's actually from an engineering magazine.

Monopoly! of course, never thought of that!

Ok People here's another Brian Teaser for you:

You are given 5 bags. There are 10 Coins in each of the bags. In four of the bags, the Coins each weigh 10 grams.  In the remaining bag,  each Coin weighs only 9 grams. All the bags and Coins look identical. You must  find out which bag has the lighter Coins.

The problem is that all the bags look identical and all the Coins look identical. You can use a scale, but it has to be a single-tray scale, not a two-tray balance scale.  Also, you may use the scale only once.

How can you find out which bag has the lighter Coins?

Puzzlers............Begin

Rhys wrote: rubberknees50 wrote: Cleopatra slipped whilst passing Anthony his viagra, broke the bowl and they both died of old age trying to manage without? not quite, but I think Freud would have something to say about your answer..

Must have been a freudian slip...............

G0ph3r wrote: Ok People here's another Brian Teaser for you: You are given 5 bags. There are 10 Coins in each of the bags. In four of the bags, the Coins each weigh 10 grams.  In the remaining bag,  each Coin weighs only 9 grams. All the bags and Coins look identical. You must  find out which bag has the lighter Coins. The problem is that all the bags look identical and all the Coins look identical. You can use a scale, but it has to be a single-tray scale, not a two-tray balance scale.  Also, you may use the scale only once. How can you find out which bag has the lighter Coins? Puzzlers............Begin

Put all the bags on the scale at once and remove each one by one. By noting the decrease in weight each time a bag is removed you will determine which one has the lighter coins in it.

Peter Fenwick wrote: Put all the bags on the scale at once and remove each one by one. By noting the decrease in weight each time a bag is removed you will determine which one has the lighter coins in it.

That's using the scales 5 times

rubberknees50 wrote: Put them in a slot machine and see which coins get rejected? Or take them down the pub and see which the landlord will exchange for beer? I should know this but it's been a long day and I have another tomorrow to look forward to!

I too have another long day ahead...Working frantically from 8am to 11am...sitting around drinking coffee and thinking of other puzzles for you guys to play with for the last 7 hours until I finish @ 6pm

Try these on for size.......

Slice the square into 4 identical sections that each have a caterpiller and a leaf, except one - she's on a  diet again!

Slice the rectangle into two sections so that you could make a square 8x8 without any holes.

Enjoy

kbannon wrote: regarding the overtaking loose wheel - was the car reversing and the wheel went the forwards direction?

No that's not it.

Do you give up yet?

kbannon wrote: Peter Fenwick wrote: A car is driving along the motorway at a constant speed when one of the wheels falls off. Assuming there is no rolling resistance from the road why does the wheel over take the car? right then! motorway... wheel off... overtake... The wheel came off, landed on/in a car in the overtaking lane

Not even close!

rubberknees50 wrote: Trying to work out if it is necessarily a road wheel.

It certainly is.

Eta.  Your son is also correct

Houlbt wrote: re: the coins.... label the bags A B C D E... take 1 coin from A, 2 from B, 3 from C, 4 from D, 5 from E. Take these coins and weigh them... if total weight is... 150.. then you've done something wrong. 149... then A is the light coins 148... then it's B 147... then it must be C etc. More importantly... Liverpool Champions of Europe. The car wheel one... not sure how to explain that though I get the concept (I think)

Is the correct Answer.

J7 VNK wrote: There's no rolling resistance on the wheel/road,  but there will be wind resistance!!  therefore the car is slowed by wind resistance and the wheel goes faster!

No that's not it. For the purpose of this there is no wind resistance.

Ok, so if it's not a trick question or has a silly answer it must be pure physics?

Can't be bothered to awaken the moths and try and remember things, or come up with a convincing equation! but it's to do with the inertial forces and the mass acting upon the wheel from the car. when the wheel comes of there's less force acting down on the wheel, and thus less friction between the wheel and the road, the force acting from the hub cancelling the rotational force on the wheel at a certain point (at the bottom of the wheel!  at all other points the wheel has a mass rotational force) when the wheel is left to freely rotate (comes of) the mass force is transferred to the wheel and less to the road resulting in a translation to horizontal movement from an accelerated rotation about it's axis. basically the wheel travels in the direction of strongest inertia tangentially!

I might look for an equation later!  but as f=ma you reduce the opposing force which is caused by friction on the mass of the car, thsu increasing the force applied to the wheel itself, so:

increased f = m(constant for the wheel) x increased a

Thinking about it I was passenger on a "Queen Mary" transporter loaded with scrap tyres once, on a winding A road, one of the tyres slipped it's lashings, fell over the side, overtook us and hit a car coming the other way square on the bonnet.

Don't know the math but it was interesting to watch!

J7 VNK wrote: Ok, so if it's not a trick question or has a silly answer it must be pure physics? Can't be bothered to awaken the moths and try and remember things, or come up with a convincing equation! but it's to do with the inertial forces and the mass acting upon the wheel from the car. when the wheel comes of there's less force acting down on the wheel, and thus less friction between the wheel and the road, the force acting from the hub cancelling the rotational force on the wheel at a certain point (at the bottom of the wheel!  at all other points the wheel has a mass rotational force) when the wheel is left to freely rotate (comes of) the mass force is transferred to the wheel and less to the road resulting in a translation to horizontal movement from an accelerated rotation about it's axis. basically the wheel travels in the direction of strongest inertia tangentially! I might look for an equation later!  but as f=ma you reduce the opposing force which is caused by friction on the mass of the car, thsu increasing the force applied to the wheel itself, so: increased f = m(constant for the wheel) x increased a

You're over thinking it. It's no where near as complicated as all that.

Do you give up yet?

right!!  I decided to think simply then!!

the wheel comes off, there's no rolling resitance, BUT if my wheel come off i'd bleeding stop!!  the wheel would therefore carry on going!!

if that's wrong I then give up

No still not it.

Ok, I'll put you out of your misery. When the wheel is on the car the weight it is supporting distorts the shape of the tyre so that it is not round i.e the contact patch of the tyre is flattened against the road. This effectively reduces the circumference of the wheel. When the wheel comes off the car it is no longer supporting the weight of the car and so is no longer distorted so it's circumference is not reduced. Assuming zero resistance, the wheel remains rotating at the same rpm as it was when attatched to the car but since it has a greater circumference it will travel further for each rotation.

Simple  

A lift is on the ground floor. There are 4 people in the lift including me.
When the lift reaches 1st floor, 1 person gets out 3 people get in.
The lift goes up to the second floor, 2 people get out 6 people get in.
It then goes up to the next floor up, no-one gets out but 12 people get in. Halfway up to the next floor up the lift cable snaps, it crashes to the floor. Everyone dies in the lift. How did I survive?

Rhys wrote: You made that one up, right?

Nope, straight out of an engineering magazine

Derek M5 wrote: Or the second floor!

Correct

Where do you think you're going with that thing?" asked the bus driver to the young boy.

"Where do you think I'm going? On this bus, of course. Why, can't I?" replied the boy.

"No, of course you can't," said the bus driver in a very annoying way. "It is forbidden to bring any object of length, width, or height greater than one meter on any bus. That thing you're carrying is longer than one meter."

"Fair enough," sighed the young boy. "It's about one meter and twenty centimeters long. But I can pay a ticket for it too."

"It's got nothing to do with a ticket," screeched the driver. "You could buy a dozen tickets, and I still would not let you ride on this bus!"

Frustration grew rapidly within the young lad. "Listen! I need to take this baseball bat to a game I am playing in. I don't drive a car. The cabbies are on strike. And it's raining. What do you expect me to do!"

I don't know, and I don't care anyway. You ain't gonna come on this bus with that bat. End of story."

Quickly, the young boy dashed into a shop next to the bus stop and came out with a package containing the bat. Smugly, with all thirty-two teeth on display, he showed the package to the bus driver. "Now can I come on the bus?"

With a snort, the bus driver pulled out a folding rule and performed a precise measurement. Scowling, he waved in the smug young lad.

How did the boy manage to pack a 1.2 meter baseball bat into a package less than one meter?

How many black dots?

what is represented by this?

mce
mce
mce

Pete323 wrote: what is represented by this?   mce mce mce

See how they run...

G0ph3r wrote: Pete323 wrote: what is represented by this?   mce mce mce See how they run...

no

Three mice with no i's = Three blind mice

G0ph3r wrote: Three mice with no i's = Three blind mice

correct

rubberknees50 wrote: I was thinking more like 2,3,5&10. It's got to be able to weigh from 1-40, so if you put the 2 on one side and the 3 on the other you could weigh one, they add up to 20 so do it twice and you get 40. Not sure if it works all the way though.

Is on the right track.

kbannon wrote: thats where I got my 20!

You've given a total weight, not individual weights.  The combination individual weights allow for the range from 1 to 40 Pounds.  So what are the weights of each stone?

It isn't so obvious as you will soon discover...Hah hahahahahaha hic!

Horsetan
your theory is sound... but apply a little mathematics and factor in what the question is asking.

Derek M5 wrote: http://uk.download.yahoo.com/ne/fu/attachments/bubblewrap.swf - http://uk.download.yahoo.com/ne/fu/attachments/bubblewrap.sw f

Ahhhhhhhhh! Stress relief!!  

eta. wrote: Son's answer is it correct? stones must weigh 1lb, 3lb, 9lbs and 27lb

Your son is correct. However, can he justify how he came up with those figures (apart from showing you the web page with the answer on it.)

For those of you who want to know... This is how the farmer

could weight 1 to 40 pounds of Grain using the 1, 3, 9 and 27

pound Stones:-

The following number is Unique...

8,549,176,320

Can you figure out what is so special about it?

-------------
'94 E36 320i

Well.... if it was in my bank, I would feel very special about it, and I dare say my bank manager would treat my in a very special way!

Am I close?

Derek M5 wrote: Well.... if it was in my bank, I would feel very special about it, and I dare say my bank manager would treat my in a very special way! Am I close?

I'd dare say your Bank Manager would want to marry you if it was!

but you're way off.

kbannon wrote: aha - alphabetical eight, five, four, nine, one, seven, etc.

Correct.  The digits are in alphabetical order.

A rich man's only child was kidnapped. The ransom note told him to bring a valuable diamond to a phone booth in the middle of a public park. Plainclothes police officers surrounded the park, intending to follow the criminal or his messenger. The rich man arrived at the phone booth and followed instructions but the police were powerless to prevent the diamond from leaving the park and reaching the crafty villain.

How did the villain accomplish this?

kbannon wrote: he used a monkey or bird or something and the police couldn't catch it?

This is a true story from Taiwan. When the rich man reached the phone booth he found a carrier pigeon in a cage. It had a message attached telling the man to put the diamond in a small bag which was around the pigeon's neck and to release the bird.

When the man did this the police were powerless to follow the bird as it returned across the city to its owner.

eta,

you are correct in that the paragraph is the puzzle, but the answer is in the paragraph.

Horsetan wrote: G0ph3r wrote: Nobody trying to find a solution??? Whaddye mean "nobody trying"? I've been staring at it for 20 minutes already!

Now read it